Fenrir was discovered on 12 December 2004 by Scott S. Sheppard, David L. Jewitt and Jan T. Kleyna.
The orbital period, i.e. the period it takes to complete an orbit round Saturn is 1260 days. The figure is also known as the sidereel period. The figure comes from N.A.S.A..
The Equatorial Radius of the object is 2km. The Equatorial Radius is based on the assumption of the Albedo value. The value is the radius in km of the said object at the Equator.
The albedo of the object is 0.04. The Albedo is the amount of radiation that is reflected back into space by the object.
The Semi-Major Axis of the orbit is 22450, which is the furthest point from the centre to the edge of an elliptical point.
The equatorial circumference of Fenrir is 12.6 km. The surface area of Fenrir is 50.27. The Mean orbit velocity, that is the speed at which it orbits is 4643.30 km/h. The is the average distance in km of the object is from its parent 22454800.00.
The orbital inclination, the angle at which Fenrir orbits in relation to the orbital plane is 164.9 degrees. The orbital eccentricity is 0.1332, it is the degree at which Fenrir orbits close to a circular (0) orbit as opposed to an elliptical (1) orbit.
|Designations||SXLI, S/2004 S16|
|Orbital Direction||Retrograde, opposite to the parents direction|
|Date of Discovery||12 December 2004|
|Discoverer||Scott S. Sheppard, David L. Jewitt and Jan T. Kleyna|
|Orbital Period (days)||1260|
|Equatorial Radius (km)||2|
|Semi-Major Axis (10^3 km)||22450|
|Equatorial Circumference (km)||12.6|
|Surface Area (km^2)||50.27|
|Mean Orbit Velocity (km/h)||4643.30|
|Average Orbit Distance (km)||22454800.00|
|Orbital Inclination (degrees)||164.9|
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