The location of the star in the night sky is determined by the Right Ascension (R.A.) and Declination (Dec.), these are equivalent to the Longitude and Latitude on the Earth. The Right Ascension is how far expressed in time (hh:mm:ss) the star is along the celestial equator. If the R.A. is positive then its eastwards. The Declination is how far north or south the object is compared to the celestial equator and is expressed in degrees. For 2M 0219-39, the location is 02h 19m 22.00 and -39° 25` 23.00 .
2M 0219-39 has a spectral type of M6. This means the star is a red star.
2M 0219-39 has been calculated as 0.27 times bigger than the Sun.The Sun's radius is 695,800km, therefore the star's radius is an estimated 187,866.00.km. If you need the diameter of the star, you just need to multiple the radius by 2.
The Parallax of the star is given as 25.38 which gives a calculated distance to 2M 0219-39 of 128.51 light years from the Earth or 39.40 parsecs. It would take a spaceship travelling at the speed of light, 128.51 years to get there. We don't have the technology or spaceship that can carry people over that distance yet.
The star is roughly 8,126,776.74 Astronomical Units from the Earth/Sun give or take a few. An Astronomical Unit is the distance between Earth and the Sun. The number of A.U. is the number of times that the star is from the Earth compared to the Sun.
|Primary / Proper / Traditional Name||2M 0219-39|
|Constellation's Main Star||No|
|Multiple Star System||No / Unknown|
|Right Ascension (R.A.)||02h 19m 22.00|
|Declination (Dec.)||-39° 25` 23.00|
|Distance from Earth||25.38 Parallax (milliarcseconds)|
|128.51 Light Years|
|8,126,776.74 Astronomical Units|
|Radius (x the Sun)||0.27|
|Name||Status||Mass (Jupiters)||Orbital Period (Days)||Eccentricity||Discovered||Semi-Major Axis||Periastron|
|2M 0219-39 b||Confirmed||1.1||2015||156|
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