The location of the star in the night sky is determined by the Right Ascension (R.A.) and Declination (Dec.), these are equivalent to the Longitude and Latitude on the Earth. The Right Ascension is how far expressed in time (hh:mm:ss) the star is along the celestial equator. If the R.A. is positive then its eastwards. The Declination is how far north or south the object is compared to the celestial equator and is expressed in degrees. For HATS-29, the location is 09h 00m 23.04 and -54° 53` 35.50 .
HATS-29 has a spectral type of G. This means the star is a yellow star.
HATS-29 has been calculated as 1.07 times bigger than the Sun. The Sun's radius is 695,800km, therefore the star's radius is an estimated 746,593.40.km. If you need the diameter of the star, you just need to multiple the radius by 2.
The star's metallicity is 0.080000, this value is the fractional amount of the star that is not Hydrogen (X) or Helium (Y). An older star would have a high metallicity whereas a new star would have a lower one.
The star is believed to be about 5.50 Billion years old. To put in context, the Sun is believed to be about five billion years old and the Universe is about 13.8 billion years old.
HATS-29 has an apparent magnitude of 12.60 which is how bright we see the star from Earth. Apparent Magnitude is also known as Visual Magnitude. Using the supplied Parallax value, you would get an absolute magnitude of 4.87 Magnitude, whether it be apparent/visual or absolute magnitude is measured by a number, the smaller the number, the brighter the Star is. Our own Sun is the brightest star and therefore has the lowest of all magnitudes, -26.74. A faint star will have a high number.
The Parallax of the star is given as 2.85 which gives a calculated distance to HATS-29 of 1144.83 light years from the Earth or 351.00 parsecs. It is about 6,730,026,685,981,780.79 miles from Earth.
The star is roughly 72,398,442.51 Astronomical Units from the Earth/Sun give or take a few. An Astronomical Unit is the distance between Earth and the Sun. The number of A.U. is the number of times that the star is from the Earth compared to the Sun.
A note about the calculations, when I'm talking about years, I'm talking non-leap years only (365 days).
If you were to drive there at about 120 m.p.h. in a car with an infinity engine so you didn't have to pull over for petrol, it would take you 56,083,555,716,514.84 hours or 6,402,232,387.73 years.
At the time of writing, the fastest probe so far created is the New Horizon probe which is travelling at a speed of 33,000 m.p.h. If the probe was travelling to HATS-29 then it would take 203,940,202,605.51 hours / 23,280,845.05 years to get there. Speed Ref: N.A.S.A.
It would to take a spaceship journey travelling at the speed of light, 1144.83 years to get there. We don't have the technology or spaceship that can carry people over that distance yet.
|Primary / Proper / Traditional Name||HATS-29|
|Constellation's Main Star||No|
|Multiple Star System||No / Unknown|
|Age||5.50 Billion Years Old|
|Visual / Apparent Magnitude||12.60|
|Naked Eye Visible||Requires a 4.5 - 6 Inch Telescope - Magnitudes|
|Right Ascension (R.A.)||09h 00m 23.04|
|Declination (Dec.)||-54° 53` 35.50|
|Distance from Earth||2.85 Parallax (milliarcseconds)|
|1144.83 Light Years|
|72,398,442.51 Astronomical Units|
|Radius (x the Sun)||1.07|
|Name||Status||Mass (Jupiters)||Orbital Period (Days)||Eccentricity||Discovered||Semi-Major Axis||Periastron||Inclination|
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