The location of the star in the night sky is determined by the Right Ascension (R.A.) and Declination (Dec.), these are equivalent to the Longitude and Latitude on the Earth. The Right Ascension is how far expressed in time (hh:mm:ss) the star is along the celestial equator. If the R.A. is positive then its eastwards. The Declination is how far north or south the object is compared to the celestial equator and is expressed in degrees. For WASP-90, the location is 21h 02m 07.99 and 07° 03` 24.12 .
WASP-90 has a spectral type of F6. This means the star is a yellow to white star.
WASP-90 has been calculated as 1.98 times bigger than the Sun. The Sun's radius is 695,800km, therefore the star's radius is an estimated 1,377,684.00.km. If you need the diameter of the star, you just need to multiple the radius by 2.
The star's metallicity is 0.140000, this value is the fractional amount of the star that is not Hydrogen (X) or Helium (Y). An older star would have a high metallicity whereas a new star would have a lower one.
WASP-90 has an apparent magnitude of 11.70 which is how bright we see the star from Earth. Apparent Magnitude is also known as Visual Magnitude. Using the supplied Parallax value, you would get an absolute magnitude of 4.04 Magnitude, whether it be apparent/visual or absolute magnitude is measured by a number, the smaller the number, the brighter the Star is. Our own Sun is the brightest star and therefore has the lowest of all magnitudes, -26.74. A faint star will have a high number.
The Parallax of the star is given as 2.94 which gives a calculated distance to WASP-90 of 1108.95 light years from the Earth or 340.00 parsecs. It is about 6,519,101,607,591,953.22 miles from Earth.
The star is roughly 70,129,545.45 Astronomical Units from the Earth/Sun give or take a few. An Astronomical Unit is the distance between Earth and the Sun. The number of A.U. is the number of times that the star is from the Earth compared to the Sun.
A note about the calculations, when I'm talking about years, I'm talking non-leap years only (365 days).
If you were to drive there at about 120 m.p.h. in a car with an infinity engine so you didn't have to pull over for petrol, it would take you 54,325,846,729,932.94 hours or 6,201,580,676.93 years.
At the time of writing, the fastest probe so far created is the New Horizon probe which is travelling at a speed of 33,000 m.p.h. If the probe was travelling to WASP-90 then it would take 197,548,533,563.39 hours / 22,551,202.46 years to get there. Speed Ref: N.A.S.A.
It would to take a spaceship journey travelling at the speed of light, 1108.95 years to get there. We don't have the technology or spaceship that can carry people over that distance yet.
|Primary / Proper / Traditional Name||WASP-90|
|Constellation's Main Star||No|
|Multiple Star System||No / Unknown|
|Colour||Yellow - White|
|Visual / Apparent Magnitude||11.70|
|Naked Eye Visible||Requires a 4.5 - 6 Inch Telescope - Magnitudes|
|Right Ascension (R.A.)||21h 02m 07.99|
|Declination (Dec.)||07° 03` 24.12|
|Distance from Earth||2.94 Parallax (milliarcseconds)|
|1108.95 Light Years|
|70,129,545.45 Astronomical Units|
|Radius (x the Sun)||1.98|
|Name||Status||Mass (Jupiters)||Orbital Period (Days)||Eccentricity||Discovered||Semi-Major Axis||Periastron||Inclination|
There's no register feature and no need to give an email address if you don't need to. All messages will be reviewed before being displayed. Comments may be merged or altered slightly such as if an email address is given in the main body of the comment.
You can decline to give a name which if that is the case, the comment will be attributed to a random star. A name is preferred even if its a random made up one by yourself.